(x-3)(2x+1)+15=2x^2+x+6

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Solution for (x-3)(2x+1)+15=2x^2+x+6 equation: 



(x-3)(2x+1)+15=2x^2+x+6

We move all terms to the left:

(x-3)(2x+1)+15-(2x^2+x+6)=0

We get rid of parentheses

-2x^2+(x-3)(2x+1)-x-6+15=0

We multiply parentheses ..

-2x^2+(+2x^2+x-6x-3)-x-6+15=0

We add all the numbers together, and all the variables

-2x^2+(+2x^2+x-6x-3)-1x+9=0

We get rid of parentheses

-2x^2+2x^2+x-6x-1x-3+9=0

We add all the numbers together, and all the variables

-6x+6=0

We move all terms containing x to the left, all other terms to the right

-6x=-6

x=-6/-6

x=1

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